Chem 131 HELP! please!?

Let's suppose you conduct a second experiment to better identify the unknown liquid. You collect 0.17 atm of this liquid in a 1.2 L container at 25C. Then, you combust this gas by reacting it with an excess amount of oxygen gas. If the percent yield is 71% and you collect 0.21 g of water vapor, what is the identity of the unknown liquid and explain how you came to this conclusion. Again, the possible identity of the liquid is methanol (32.04g/mol) ethanol (46.07g/mol) propanol (60.10g/mol) or benzene (78.11g/mol).